Thursday, April 9, 2009
Monday, April 6, 2009
Question to Prove Rectangle Inscribed the Circle Properties
Topic : Rectangle Inscribed the Circle
Question : If RTCE is a rectangle, then show that RC is the diameter of the circle.
Solution :
Since ∟RTC = 90º
So measure of arc REC = 180
mREC = 180º
This shows that the arc REC is half of the circle as the total measure of circle is 180º X 2 = 360º
That means arc REC forms a semi circle
Hence RC passes through the center of the circle or we can say that RC is the diameter of the circle.
Hence proved.
Question : If RTCE is a rectangle, then show that RC is the diameter of the circle.
Solution :
Since ∟RTC = 90º
So measure of arc REC = 180
mREC = 180º
This shows that the arc REC is half of the circle as the total measure of circle is 180º X 2 = 360º
That means arc REC forms a semi circle
Hence RC passes through the center of the circle or we can say that RC is the diameter of the circle.
Hence proved.
Labels:
Circles and Rectangle
Tuesday, March 31, 2009
Question to Draw Box Plot for a Collection of Data
Topic : Box Plot
Question : In a survey of the cafeteria food at Metropiolis Middle School, 50 students were asked to rate how well they liked the lunches on a scale of 1 to 10, with 1 being the lowest rating and 10 being the highest rating. The box plot was made from the collected data.
What percent of the students in the sample rated the cafeteria food between 5.75 and 9
Solution :
First Quartile = Q1 = 5.75
That is 25% of students lie between 3 and 5.75
Second Quartile = Q2 = 6.5
That is 50% of students lie between 3 and 6.5
Third Quartile = Q3 = 8
That is 75% of the students lie between 3 and 8
100% of students lie between 3 and 9
So the % of students who lie between 5.75 and 9 = 100% - 25% = 75%
and Answer is 75%
Question : In a survey of the cafeteria food at Metropiolis Middle School, 50 students were asked to rate how well they liked the lunches on a scale of 1 to 10, with 1 being the lowest rating and 10 being the highest rating. The box plot was made from the collected data.
What percent of the students in the sample rated the cafeteria food between 5.75 and 9
Solution :
First Quartile = Q1 = 5.75
That is 25% of students lie between 3 and 5.75
Second Quartile = Q2 = 6.5
That is 50% of students lie between 3 and 6.5
Third Quartile = Q3 = 8
That is 75% of the students lie between 3 and 8
100% of students lie between 3 and 9
So the % of students who lie between 5.75 and 9 = 100% - 25% = 75%
and Answer is 75%
Labels:
Box Plot
Monday, March 23, 2009
Tuesday, March 17, 2009
Equation of Circle Passing Through Point (-1,-9)
Topic : Equation of Circle
Question : Write the Standard from of the equation of the circle that passes through the given point (-1,-9) and whose center is the origin.
Solution :
The Standard equation of the circle with center at origin (0,0) is x² + y² = r²
r being its radius as x² + y² = r² passes through (-1,-9) we have
(-1)² + (-9)² = r²
or
r² = 1 + 81 = 82
So the required circle is x² + y² = 82
Question : Write the Standard from of the equation of the circle that passes through the given point (-1,-9) and whose center is the origin.
Solution :
The Standard equation of the circle with center at origin (0,0) is x² + y² = r²
r being its radius as x² + y² = r² passes through (-1,-9) we have
(-1)² + (-9)² = r²
or
r² = 1 + 81 = 82
So the required circle is x² + y² = 82
Labels:
Equation of Circle
Thursday, March 12, 2009
Problem on Simultaneous Equation
Topic : Simultaneous Equation
Question : Solve and find the value of x and z
x + z = 22
x +6z = 50
Solution :
x + z = 22---------------(1)
x +6z = 50--------------(2)
Subtracting second equation from first equation
we get, -5z = -28
divide both sides by -5
So z = 5.6
Substitute the value of z in equation (1)
x+5.6 = 22
x=22-5.6
x= 16.4
So the value of x = 16.4 and z = 5.6
Question : Solve and find the value of x and z
x + z = 22
x +6z = 50
Solution :
x + z = 22---------------(1)
x +6z = 50--------------(2)
Subtracting second equation from first equation
we get, -5z = -28
divide both sides by -5
So z = 5.6
Substitute the value of z in equation (1)
x+5.6 = 22
x=22-5.6
x= 16.4
So the value of x = 16.4 and z = 5.6
Labels:
Simulatneous Equation
Friday, March 6, 2009
Problem on Square Roots
Topic : Square Roots
Question : Solve:
(x – 2)^2 = 4
Solution :
Taking square roots on both the sides, we get
(x – 2) = ± rad(4)
Case (i)
x – 2 = 2
Add 2 on both the sides of the equation
x – 2 + 2 = 2 + 2
x = 4
Case (ii)
x – 2 = -2
Add 2 on both the sides of the equation
x – 2 + 2 = -2 + 2
x = 0
The solutions are x = 0, 4
Question : Solve:
(x – 2)^2 = 4
Solution :
Taking square roots on both the sides, we get
(x – 2) = ± rad(4)
Case (i)
x – 2 = 2
Add 2 on both the sides of the equation
x – 2 + 2 = 2 + 2
x = 4
Case (ii)
x – 2 = -2
Add 2 on both the sides of the equation
x – 2 + 2 = -2 + 2
x = 0
The solutions are x = 0, 4
Labels:
Surds
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