Topic : Equation of Circle
Question : Write the Standard from of the equation of the circle that passes through the given point (-1,-9) and whose center is the origin.
Solution :
The Standard equation of the circle with center at origin (0,0) is x² + y² = r²
r being its radius as x² + y² = r² passes through (-1,-9) we have
(-1)² + (-9)² = r²
or
r² = 1 + 81 = 82
So the required circle is x² + y² = 82
Question : Write the Standard from of the equation of the circle that passes through the given point (-1,-9) and whose center is the origin.
Solution :
The Standard equation of the circle with center at origin (0,0) is x² + y² = r²
r being its radius as x² + y² = r² passes through (-1,-9) we have
(-1)² + (-9)² = r²
or
r² = 1 + 81 = 82
So the required circle is x² + y² = 82
